0=-0.055x^2+116x-5280

Solution for 0=-0.055x^2+116x-5280 equation:

0=-0.055x^2+116x-5280

We move all terms to the left:

0-(-0.055x^2+116x-5280)=0

We add all the numbers together, and all the variables

-(-0.055x^2+116x-5280)=0

We get rid of parentheses

0.055x^2-116x+5280=0

a = 0.055; b = -116; c = +5280;
Δ = b2-4ac
Δ = -1162-4·0.055·5280
Δ = 12294.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-116)-\sqrt{12294.4}}{2*0.055}=\frac{116-\sqrt{12294.4}}{0.11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-116)+\sqrt{12294.4}}{2*0.055}=\frac{116+\sqrt{12294.4}}{0.11}
$